在category.php 行 272处查找

$attr_list = $db->getAll($sql);
字样然后下面增加如下代码 
从phpsir_filter_code_start 到 phpsir_filter_code_end 中间部分

$attr_list = $db->getAll($sql);
//phpsir_filter_code_start
                $phpsir_tmp=$attr_list[0];
                $phpsir_sql= "select attr_values from " . $ecs->table('attribute') . " WHERE attr_id = '$phpsir_tmp[attr_id]' ";
                $phpsir_attribute = $db->getOne($phpsir_sql);  
                $phpsir_ga = explode("\n",$phpsir_attribute);
                $phpsir_new_attr_list = array();
                foreach($attr_list as $kk=>$vv)
                {
                    foreach($phpsir_ga as $kkk => $vvv){
                        if(trim($vv['attr_value']) == trim($vvv))
                        {
                            $phpsir_new_attr_list[$kkk] = $vv;
                        }
                    }
                }
                ksort($phpsir_new_attr_list);
                $attr_list = $phpsir_new_attr_list;
//phpsir_filter_code_end

前台显示例子如下

代码在上面，或者如下图

http://bbs.ecshop.com/viewthread.php?tid=159368

原始问题如上，截屏如下

解决问题是看  includes\lib_order.php 的函数 get_total_bonus

原来代码是如下的

/* 按订单发的红包 */
$sql = “SELECT FLOOR(‘$amount’ / min_amount) * type_money ” .
“FROM ” . $GLOBALS[‘ecs’]->table(‘bonus_type’) .
” WHERE send_type = ‘” . SEND_BY_ORDER . “‘ ” .
” AND send_start_date <= ‘$today’ ” .
“AND send_end_date >= ‘$today’ ” .
“AND min_amount > 0 “;

很显然，凡是比较最低订单金额大的订单，都会导致商的个数的红包，我们其实只要发的是最大的红包那个就可以了,所以我们修改如下

/* 按订单发的红包 */
$sql = “SELECT FLOOR(‘$amount’ / min_amount) * type_money ” .
“FROM ” . $GLOBALS[‘ecs’]->table(‘bonus_type’) .
” WHERE send_type = ‘” . SEND_BY_ORDER . “‘ ” .
” AND send_start_date <= ‘$today’ ” .
“AND send_end_date >= ‘$today’ ” .
“AND min_amount > 0 and min_amount <= ‘$amount’ order by min_amount desc limit 1 “; 注意上面这行的条件增加了
and min_amount <= ‘$amount’ order by min_amount desc limit 1
就是说最接近订单额度的红包发放条件，取一个即可